6x + 3y = 9

2x + 3y = 1

Solve the system of equations.

A) x = 2, y = - 1

B) x = - 1, y = 2

C) x = - 1/2, y = 3

D) x = 3, y = - 1/2

Solution 1 ▶6 (x) + 3 (y) = 9

Solution 2 ▶2 (x) + 3 (y) = 1

Graphic organizer ▶3 (y) + 6 (x) = 9⬇

3 (y) + 2 (x) = 1

Solution 2⬇

keep in mind the '2' becomes a negative!

▶3 (y) = - 2 (x) + 1

▶ (y) = - 2 (x) : 3 + 1 : 3

Solution 1⬇

x-intercept

6 (x) + 3 (-2) (x) : 3+1:3) = 9

▶ 4 (x) = 8

▶4 (?) = 8

▶x = 2

y-intercept⬇

▶ (y) = - 2 (x) : 3+1:3

▶ (y) = (-2:3) (2) + 1:3 = - 1

▶y = - 1

x-intercept: 2

y-intercept: - 1

So, therefore your answer for this problem would have to be option A. x = 2, y = - 1

6x + 3y = 9

2x + 3y = 1

subtracting both equation we get

4x = 8 then

x = 2 and putting the value of x in any one equation we get the value of y

that is y = - 1

options A is correct