What are solutions to the equation below x^2 + 3x-18=0

x^2+3x-18=0

(x+6) (x-3)

x=3,-6

You could plug it into a calculator to get your solutions or you could factor. Let's factor.

You need to find two numbers that when multiplied get you - 18 and when added get you 3.

Let's get factors of - 18:

1 * - 18

2 * - 9

3 * - 6

The only factors that can get you that are - 3 and 6.

(x-3) (x+6) = 0

Set each factor equal to 0 and solve.

x-3=0

x=3

x+6=0

x=-6

Your solutions are 3 and - 6.