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7 February, 06:41

If x=3+root8 and y = 3 - root 8 find 1/x^2+1/y^2

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  1. 7 February, 08:25
    0
    34

    Step-by-step explanation:

    x=3+√8

    y = 3-√8

    now,

    1/x^2+1/y^2

    =1 / (3+√8) ² + 1 / (3-√8) ²

    = [ (3-√8) ² + (3+√8) ²] / (3+√8) ² (3-√8) ² [L. C. M = (3+√8) ² (3-√8) ² ]

    =[ (3-√8+3+√8) ²-2 (3-√8) (3+√8) ] / [ (3+√8) (3-√8) ]²

    =[6²-2. (3²-√8²) ] / (3²-√8²) ² [ a² + b² = (a+b) ²-2ab]

    =[36-2 (9-8) ] / (9-8) ²

    =[36-2.1] / 1²

    =34
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