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19 April, 22:21

The roots of the function fx=x2-2x-3 are shown. What is the missing number?

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Answers (2)
  1. 20 April, 00:05
    0
    x = 3, - 1

    Step-by-step explanation:

    x² - 2x - 3

    x² - 3x + x - 3

    x (x - 3) + (x - 3)

    (x - 3) (x + 1) = 0

    x = 3, - 1
  2. 20 April, 00:59
    0
    The roots are x=3 x=-1

    Step-by-step explanation:

    fx=x^2-2x-3

    To find the roots we set the equation to 0

    0 = x^2 - 2x-3

    Factor what two numbers multiply to - 3 and add to - 2

    -3*1 = - 3

    -3+1 = - 2

    0 = (x-3) (x+1)

    Using the zero product property

    x-3 = 0 x+1 = 0

    x=3 x=-1

    The roots are x=3 x=-1
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