Which function has only one x-intercept at (-6, 0) ?

f (x) = x (x - 6)

Of (x) = (x - 6) (x - 6)

f (x) = (x + 6) (x - 6)

f (x) = (x + 6) (x + 6)

Question

Mathematics

Terry Faulkner

13 June, 20:52

Which function has only one x-intercept at (-6, 0) ?

f (x) = x (x - 6)

Of (x) = (x - 6) (x - 6)

f (x) = (x + 6) (x - 6)

f (x) = (x + 6) (x + 6)

+3

Answers (1)

Know the Answer?

Abel Cole · Answer 1

Answer: f (x) = (x+6) (x+6)

Step-by-step explanation:

To find the x intercept you want each set of parenthesis to equal out to zero. Therefore to have an x intercept of only - 6, then both sets of parenthesis must be (x+6) because - 6 + 6 = 0.

Which function has only one x-intercept at (-6, 0) ?f (x) = x (x - 6)Of (x) = (x - 6) (x - 6)f (x) = (x + 6) (x - 6)f (x) = (x + 6) (x + 6)

Which function has only one x-intercept at (-6, 0) ?

f (x) = x (x - 6)

Of (x) = (x - 6) (x - 6)

f (x) = (x + 6) (x - 6)

f (x) = (x + 6) (x + 6)