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13 June, 20:48

The table below shows the distance d (t) in feet that an object travels in t seconds: t (seconds) d (t) (feet) 1 15 2 60 3 135 4 240 What is the average rate of change of d (t) between 2 seconds and 4 seconds, and what does it represent?

50 ft/s; it represents the average speed of the object between 2 seconds and 4 seconds

90 ft/s; it represents the average speed of the object between 2 seconds and 4 seconds

90 ft/s; it represents the average distance traveled by the object between 2 seconds and 4 seconds

50 ft/s; it represents the average distance traveled by the object between 2 seconds and 6 seconds

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  1. 13 June, 21:26
    0
    Step-by-step explanation:

    Answer:

    Option B is correct

    The average rate of change of d (t) between 2 second and 4 second is; 90 ft/s

    and it represents the average speed of the object between 2 seconds and 4 seconds.

    Step-by-step explanation:

    Average rate of change of function is defined as the ratio of the difference in the function f (x) as it changes from a to b to the difference between a and b. Then, the average rate of change is denoted as A (x).

    As per the given statement, the distance d (t) is in feet and t is the time in second.

    To find the average rate of change of d (t) between 2 seconds and 4 seconds.

    From the table we have;

    at t = 2, d (2) = 60

    and

    at t = 4, d (4) = 240.

    Then, by the definition of average rate of change;

    =

    Simplify:

    therefore, the average rate of change of d (t) between 2 second and 4 second is; 90 ft/s and it represents the average speed of the object between 2 seconds and 4 seconds.
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