What is the vertex of this function f (x) = x^2+12x

(-6, 36)

Step-by-step explanation:

The standard form: ax^2 + bx + c

In this case:

a is 1

b is 12

c is 0

Calculate - b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of - b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

-12 / (2 x 1)

-12 / 2

-6

You log - 6 in the function

f (x) = x^2 + 12x

f (-6) = (-6) ^2 + 12 (-6)

= 36 + (-72)

= 36 - 72

= 36

I hope this