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20 December, 07:41

What is the vertex of this function f (x) = x^2+12x

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  1. 20 December, 08:20
    0
    (-6, 36)

    Step-by-step explanation:

    The standard form: ax^2 + bx + c

    In this case:

    a is 1

    b is 12

    c is 0

    Calculate - b / 2a. This is the x-coordinate of the vertex.

    To find the y-coordinate of the vertex, simply plug the value of - b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

    -12 / (2 x 1)

    -12 / 2

    -6

    You log - 6 in the function

    f (x) = x^2 + 12x

    f (-6) = (-6) ^2 + 12 (-6)

    = 36 + (-72)

    = 36 - 72

    = 36

    I hope this
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