What are the restrictions for (x^2+10x+25) / (x^2-3x-28)

0,14

-4,7

0,7

4,7

The answer is - 4,7

The denominator can't equal zero. Factor the denominator:

x^2 - 3x - 28=

(X - 7) (x + 4); next set each set of parentheses equal to 0;

x - 7 = 0; so x=7 is one value

x + 4 = 0; so x=-4 is the other

Remember, x = 7 and x = - 4 make the denominator zero, which is a "restriction" because you can't divide by zero.