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31 January, 22:35

A pair of dice is rolled. find the probability of rolling a sum between 3 and 8

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  1. 31 January, 22:46
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    It does not say is btw 3 and 8 inclusive so we can assume is sum 4,5,6, and 7

    Sum 4 is made 1+3, 2+2

    Sum 5 is made 1+4, 2+3

    Sum 6 is made 1+5, 2+4, 3+3

    Sum 7 is made 1+6, 2+5, 3+4

    So there are 10 ways to make the sum 4,5,6,7

    The total number of possible sums 10+11=21

    Sum of 2 is 1+1

    Sum of 3 is 1+2

    Sum of 8 is 2+6, 3+5, 4+4

    Sum of 9 is 3+6, 4+5

    Sum of 10 is 4+6, 5+5

    Sum of 11 is 5+6

    Sum of 12 is 6+6

    Probably = 10/21
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