1. A bowling ball with a mass of 2-kg sits on top of a building that is 40 meters tall.

Solve for GPE

Formula:

Plug in numbers:

Answer (with units)

2. A bowling ball with a mass of 2-kg rolls at a speed of 5 m/s on the roof of the building that is 40 tall.

Solve for GPE and KE

GPE Formula:

KE Formula:

Plug in numbers:

Plug in numbers:

Answer (with units)

Answer (with units)

3. A 2-kg bowling ball rolls at a speed of 10 m/s on the ground.

Solve for KE:

Formula:

Plug in numbers:

Answer (with units)

4. A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5 m/s.

Solve for GPE and KE

GPE Formula:

KE Formula:

Plug in numbers:

Plug in numbers:

Answer (with units)

Answer (with units)

45

Step-by-step explanation:

bc

1. A 2-kg bowling ball sits on top of a building that is 40 meters tall. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:

KE = 0 (because velocity is 0)

PE = mgh = 2kg*9.8m/s^2*40m = 784 joule

2. A 2-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 40 tall. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:

Both

KE = [1/2]m*v^2 = [1/2] (2kg) (5m/s) ^2 = 25 joul

PE = mgh = 40 joule

3. A 2-kg bowling ball rolls at a speed of 10 m/s on the ground. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:

KE = [1/2]m (v^2) = [1/2]2kg * (10m/s) ^2 = 100 joule

GPE = mgh = 0

1. A 1,000-kg car has 50,000 joules of kinetic energy. What is its speed?

KE = [1/2]m (v^2) = > v = √[2KE/m] = √[2*50,000joules/1000kg] = 10m/s

2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?

GPE = mgh = > h = GPE / (mg) = 39,200 joules / (200kg * 9.8m/s^2) = 20m

3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?

KE = [1/2]m (v^2) = > v = √ [ 2KE/m] = √[2*12.5 j / 1kg] = 7.9 m/s

GPE = mgh = > h = GPE / (mg) = 98 / (1kg*9.8m/s^2) = 10 m

Step-by-step explanation:

bc someone else said it