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9 April, 19:16

Find three consecutive even integers. Such that 4 times of first integer is 18 more than the sum of second and third integers

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  1. 9 April, 22:38
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    integers:

    x

    x + 2

    x + 4

    4x - (x + 4) = 2 (x + 2) + 6

    3x - 4 = 2x + 4 + 6

    3x - 4 = 2x + 10

    x = 14

    integers: 14, 16, 18

    check answer: 4 (14) - 18 = 2 (16) + 6

    38 = 38
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