Find all solutions for a triangle with a=26, b=29, and A=58

a=26

b=29

A=58 degrees

Using the Law of sines we can fine angle B:

(sin A) / a = (sin B) / b multiply both sides by b

sin B = (sin A) (b / a)

sin B = (sin 58) (29/26)

sin B = 0.9458997995

B = arcsin 0.9458997995

B = 71 degrees approximately

C = 180 - (A + B)

C = 180 - (58 + 71)

C = 51 degrees

(sin A) / a = (sin C) / c

c = a ((sin C) / (sin A))

c = 26 (sin (51) / sin (58))

c = 23.83