Ask Question
Yesterday, 10:14

Phillip has 52 new stickers. If he puts an equal number of stickers on each of 6 blank pages in his sticker book, how many stickers does he have left over?

+2
Answers (2)
  1. Yesterday, 11:11
    0
    4 stickers

    Step-by-step explanation:

    We can solve this problem using two methods:

    First one, we can get the 52 stickers and subtract 6 over and over until we can't subtract 6 anymore, so:

    52 - 6 = 46

    46 - 6 = 40

    40 - 6 = 34

    34 - 6 = 28

    28 - 6 = 22

    22 - 6 = 16

    16 - 6 = 10

    10 - 6 = 4

    Now we can't subtract 6 anymore, so there were left 4 stickers

    The second method is dividing the number of stickers (52) by the number of stickers put in each page (6), so the result will be the number of pages used, and the rest of the division will be the number of stickers left:

    52 divided by 6 is equal to 8, and the rest is 4.

    So Phillip has 4 stickers left over
  2. Yesterday, 11:30
    0
    He would have 4 stickers leftover

    Step-by-step explanation:

    In this question, we are asked to calculate the remaining number of stickers if Phillip puts exact number of stickers on 6 blank pages.

    This question is quite straight forward. What we are asked simply is that in each of the pages, there must be equal number of stickers and that after putting same number of stickers on each pages, how many do we have left.

    This is like a question of asking how many times can we have six stickers at a time out of 52 stickers.

    Now what to do is to look for the multiple of 6 that is closest to 52. This is simply 48.

    This means we should have 8 stickers per page. The remainder of the number of stickers would thus be 52-48 = 4 stickers
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Phillip has 52 new stickers. If he puts an equal number of stickers on each of 6 blank pages in his sticker book, how many stickers does he ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers