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23 August, 03:31

Obtain all zeros of x^4-7x^2+12, if two numbers of its zeros are √3 and - √3

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  1. 23 August, 05:52
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    Step-by-step explanation:

    x^2=u

    u^2-7u+12=0

    (u-3) (u-4) = 0

    u=3,4

    x^2=3,4

    x^2=3

    x = ±√3

    x^2 = 4

    x=±2
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