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28 November, 14:03

Moises is rolling a number cube, with sides numbered 1 through 6, 30 times. How many times should he expect to roll an odd number?

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  1. 28 November, 17:44
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    15 times

    Step-by-step explanation:

    To find the expected count you have to multiply the probability of the favorable event with the number of repetitions/rolls. For a fair dice, every number will have the same probability to occur. The dice have number 1 to 6 which mean there are 3 odd numbers (2, 4, 6) out of 6 possible number.

    Then the probability for odd number will be: 3/6 = 1/2

    The expected count of odd numbers in 30 rolls will be = 1/2 * 30 = 15 times.
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