What is the probability of getting a sum 9 from two throws of a dice?

1/9

Step-by-step explanation:

Probability is:

# of desired outcomes/# of total outcomes

First, we can find the number of total outcomes.

6*6=36

They are as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

This is where (here is the value of the first dice role, here is the value of the second dice roll)

Now, I am going to bold all the outcomes that add up to 9.

Notice that there are 4.

So there are 4 desired outcomes and 36 total outcomes.

4/36

Simplify

1/9