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15 April, 23:07

Find the dimensions of a rectangle, length 7m less than three times the width and the area of the rectangle is 66m^2.

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  1. 15 April, 23:44
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    We know: length of a rectangle is 7m less than three times the width.

    So let's set the length to l, width to w.

    And we can get that l = 3w-7.

    We also know that the area of the rectangle is 66 m^2.

    Thus, l*w = 66.

    So we have:

    function 1: l=3w-7

    function 2: l*w=66

    plug function 1 to 2.

    (3w-7) * w=66

    3w^2-7w-66=0

    w=6 and - 11/3.

    And the width of a rectangle can not be negative.

    So: w=6.

    Plug w=6 back to function 1 or 2, either way is correct and can give you the length. In this case, I will plug it back to function 1.

    l=3*6-7=11.

    So: the width of the rectangle is 6, and the length of the rectangle is 11.
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