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30 May, 07:24

Using the digits 1 to 9 at most one time each place a digit in each box to create an equation where X is a negative value serve you equation to prove your answer

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Answers (2)
  1. 30 May, 07:48
    0
    The correct question is:

    Using the digits 1 to 9 at most one time each place a digit in each box to create an equation where x is a negative value solve your equation to prove your answer.

    __x + __ = __

    Answer:

    1. 9x + 8 = 1

    2. 7x + 6 = 2

    3. 5x + 4 = 3

    Step-by-step explanation:

    1. 9x + 8 = 1

    Subtract 8 from both sides

    9x = 1 - 8

    9x = - 7

    Divide both sides by 9

    x = - 7/9

    2. 7x + 6 = 2

    Subtract 6 from both sides

    7x = 2 - 6

    7x = - 4

    Divide both sides by 7

    x = - 4/7

    3. 5x + 4 = 3

    Subtract 4 from both sides

    5x = 3 - 4

    5x = - 1

    Divide both sides by 5

    x = - 1/5
  2. 30 May, 10:40
    0
    The solution set of equations assuming x as a negative value can go from:

    x + 9 = 2, that gives us the least possible negative value of - 7 to:

    x + 3 = 2, that gives us the highest negative value of - 1 to x

    The only condition is that the second term of the equation should be a higher number than the result.

    Step-by-step explanation:

    If x is a negative value, let's create the set of equations using digits from 1 to 9 one time, this way:

    a. x + 9 = 2

    x = 2 - 9

    x = - 7

    b. x + 9 = 3

    x = 3 - 9

    x = - 6

    c. x + 3 = 2

    x = 2 - 3

    x = - 1

    d. x + 4 = 2

    x = 2 - 4

    x = - 2

    e. x + 6 = 5

    x = 5 - 6

    x = - 1
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