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30 October, 18:46

Eliminate the parameter. x = t - 3, y = t2 + 5

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  1. 30 October, 21:03
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    y = x^2 + 6x+14

    Step-by-step explanation:

    x = t - 3, y = t^2 + 5

    x=t-3

    Add 3 to each side

    x+3 = t-3+3

    x+3 = t

    Substitute into the second equation

    y = t^2 + 5

    y = (x+3) ^2 + 5

    Foil the first term

    y = (x+3) (x+3) + 5

    y = (x^2 + 3x+3x+9) + 5

    y = x^2 + 6x+9) + 5

    y = x^2 + 6x+14
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