The perimeter of a rectangle is 312 meters. If the length is six meters more than five times the width what are the length and the width?

Solve the problem below by:

Writing the introductory 'let' statement to specify what the variable x will represent (if there is more than one unknown, express each of them in terms of x).

Translating the wording of the question into a linear equation with x.

Solving the equation.

Writing the concluding statement that provides the answer to the problem.

Question

Mathematics

Isaiah George

21 August, 12:44

The perimeter of a rectangle is 312 meters. If the length is six meters more than five times the width what are the length and the width?

Solve the problem below by:

Writing the introductory 'let' statement to specify what the variable x will represent (if there is more than one unknown, express each of them in terms of x).

Translating the wording of the question into a linear equation with x.

Solving the equation.

Writing the concluding statement that provides the answer to the problem.

+5

Answers (1)

Know the Answer?

Frank Contreras · Answer 1

Answer: width = 25 meters, length = 131 meters

Step-by-step explanation:

Given: Perimeter = 312

Let x represent the width (w), then length (L) = 5x + 6

Perimeter = 2L + 2w

312 = 2 (5x + 6) + 2 (x)

312 = 10x + 12 + 2x

312 = 12x + 12

- 12 - 12

300 = 12x

:12 : 12

25 = x

width = x = 25

length = 5x + 6 = 5 (25) + 6 = 131

The width of the rectangle is 25 meters and the length is 131 meters.