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15 July, 06:45

The hypotenuse of a triangle is 26 feet long one leg of the triangle is 14 feet longer than the other leg find the lengths of the legs of the triangle

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  1. 15 July, 09:19
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    I'm assuming this is a right angled triangle

    By Pythagoras:_

    x^2 + (x + 14) ^2 = 26^2 where x = length of the shortest leg

    x^2 + x^2 + 28x + 196 = 676

    2x^2 + 28x - 480 = 0

    x^2 + 14x - 240 = 0

    (x + 24) (x - 10) = 0

    so shortest side x = 10 feet (we ignore the negative root)

    So the lengths of the legs is 10 and 24 feet.
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