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29 April, 15:31

Solve the quadratic equation by factoring. 8x^2+21=-59x

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Answers (2)
  1. 29 April, 17:11
    0
    Solve your equation step-by-step.

    8x^2+21=-59x

    Subtract - 59x from both sides.

    8x^2+21--59x=-59x--59x

    8x^2+59x+21=0

    Factor left side of equation.

    (8x+3) (x+7) = 0

    Set factors equal to 0.

    8x+3=0 or x+7=0

    x=-3/8

    or

    x=-7
  2. 29 April, 17:32
    0
    Make one side zero

    add 59x to both sides

    8x^2+59x+21=0

    factor

    to find the factor in

    ax^2+bx+c form when a>1

    multiply a and c together

    find what 2 numbers add up to b and multiply to ac so

    a=8

    b=59

    c=21

    ac=8 times 21=168

    factors that add up to 59 and multiply to get 168

    the numbers are 56 and 3

    3 and 56 are the numbers since 3 times 56=168 and 3+56=168 so

    split it up

    8x^2+56x+3x+21=0

    group

    (8x^2+56x) + (3x+21) = 0

    undistribute

    (8x) (x+7) + (3) (x+7) = 0

    reverse distribute

    (8x+3) (x+7) = 0

    set each to zero

    8x+3=0

    subtract 3

    8x=-3

    divide by 8

    x=-3/8

    x+7=0

    subtract 7

    x=-7

    x=-7 or - 3/8
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