How do you solve this by completing the square? 6x^2-10x+4=0 I got 3x-5/2=+or-√17/2. I'm not sure.

Well you could factor out the 2 in the equation

6=3*2

10=5*2

4=2*2

so

6x^2-10x+4=2 (3x^2-5x+2) so

factor 3x^2-5x+2 and get

(x-1) (3x-2) = 0

so xy=0 then x and/or y=0 so

x-1=0

x=1

3x-2=0

3x=2

x=2/3

x=1 or 2/3