What is the factored form of y=x^3+3x^2-x-3 and what the zeros

y = x³ + 3x² - x - 3

0 = x³ + 3x² - x - 3

0 = x² (x) + x² (3) - 1 (x) - 1 (3)

0 = x² (x + 3) - 1 (x + 3)

0 = (x² - 1) (x + 3)

0 = (x² + x - x - 1) (x + 3)

0 = (x (x) + x (1) - 1 (x) - 1 (1)) (x + 3)

0 = (x (x + 1) - 1 (x + 1)) (x + 3)

0 = (x - 1) (x + 1) (x + 3)

0 = x - 1 or 0 = x + 1 or 0 = x + 3

+ 1 + 1 - 1 - 1 - 3 - 3

1 = x or - 1 = x or - 3 = x

Solution Set: {-3, - 1, 1}