Each dimension of a right triangle with legs of length 6 cm and 8 cm and a hypotenuse of length 10 cm is multiplied by 1/2 to form a similar right triangle. How is the ratio of perimeters related to the ratio of corresponding sides? How is the ratio of areas related to the ratio of corresponding sides?

Question

Mathematics

Brandi

7 February, 01:52

Each dimension of a right triangle with legs of length 6 cm and 8 cm and a hypotenuse of length 10 cm is multiplied by 1/2 to form a similar right triangle. How is the ratio of perimeters related to the ratio of corresponding sides? How is the ratio of areas related to the ratio of corresponding sides?

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Augie · Answer 1

Perimeter of original triangle: 6+8+10=24 cm

Perimeter of new triangle: 3+4+5=12 cm (You get 3, 4, and 5 from dividing 6, 8. and 10 by 2.)

Ratio of original to new is 24 to 12, simplified to 2 to 1.

The ratio of the perimeter is the ratio of the corresponding sides, as the original measurements are two times the length of the new measurements.

Area of original triangle: (6x8) / 2=24 cm^2

Area of new triangle: (3x4) / 2=6 cm^2

Ratio of original to new is 24 to 6, simplified to 4 to 1.