What is the completely factored form of f (x) = 6x3 - 13x2 - 4x + 15?

A.) (x + 1) (6x2 - 19x + 15)

B.) (x + 1) 2 (2x - 3)

C.) (x + 1) (3x - 2) (5x - 3)

D.) (x + 1) (2x - 3) (3x - 5)

Question

Mathematics

Shaniya Beltran

22 January, 08:40

What is the completely factored form of f (x) = 6x3 - 13x2 - 4x + 15?

A.) (x + 1) (6x2 - 19x + 15)

B.) (x + 1) 2 (2x - 3)

C.) (x + 1) (3x - 2) (5x - 3)

D.) (x + 1) (2x - 3) (3x - 5)

+3

Answers (1)

Know the Answer?

Jose Schneider · Answer 1

D). (x + 1) (2x-3) (3x - 5) Choice A is a correct factorization but it is not fully factored. Choice C takes A one step further and factors the second term into two terms that are then the completely factored form. You can test this result by multiplying the terms above together, combining like terms and you will get the original term f (x).

What is the completely factored form of f (x) = 6x3 - 13x2 - 4x + 15?A.) (x + 1) (6x2 - 19x + 15)B.) (x + 1) 2 (2x - 3)C.) (x + 1) (3x - 2) (5x - 3)D.) (x + 1) (2x - 3) (3x - 5)

What is the completely factored form of f (x) = 6x3 - 13x2 - 4x + 15?

A.) (x + 1) (6x2 - 19x + 15)

B.) (x + 1) 2 (2x - 3)

C.) (x + 1) (3x - 2) (5x - 3)

D.) (x + 1) (2x - 3) (3x - 5)