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12 September, 17:50

Find the zeros of y = 3x^2+3x

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  1. 12 September, 21:35
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    The zeros of y = 3x^2+3x means to solve for the values of x when y = 0

    y = 3x² + 3x = 0

    y = 3x²+3x = 0

    3x²+3x = 0 Factorize

    3x (x + 1) = 0

    3x = 0, or (x + 1) = 0

    From 3x = 0, x = 0/3 = 0

    From (x + 1) = 0, x = 0 - 1 = - 1.

    Therefore the zeros are 0 and - 1.
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