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25 June, 16:37

A new neighborhood activity complex is being built in del rio. the perimeter of the rectangular playing field is 272 yards. the length of the field is 5 yards less than double the width. what are the dimensions of the playing field?

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  1. 25 June, 20:04
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    Let the width be x, double the width is 2x, then the length is 2x - 5

    Perimeter = 2 (l + w) = 2 (2x - 5 + 2x) = 2 (4x - 5) = 8x - 10 = 272

    8x = 272 + 10 = 282

    x = 282/8 = 35.25

    Therefore, width is 35.25 yards and length is 2 (35.25) - 5 = 65.5
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