A number x is no more than 9 units away from 8. Write and solve an absolute-value inequality to show the range of possible values of x.

|x - 8| ≤ 9

-1 ≤ x ≤ 17

|x + 8| ≤ 9

-17 ≤ x ≤ 1

|x - 9| ≤ 8

1 ≤ x ≤ 17

|x + 9| ≤ 8

-17 ≤ x ≤ - 1

The answer is a (|x - 8| ≤ 9 and - 1 ≤ x ≤ 17) Because the difference between x and 8 can't be greater than 9, but it can be less than or equal to it, and because the range that x could be would be - 1 to 17, since 8 + 9 = 17 and 8 - 9 = - 1.