Determine the zeros of each function by factoring:

a) f (x) = - 2x^2-5x+12

b) f (x) = 2x^2-3x-2

A) f (x) = - 2x² - 5x + 12

0 = - 2x² - 5x + 12

0 = - 2x² - 8x + 3x + 12

0 = - 2x (x+4) + 3 (x+4)

0 = (-2x+3) + (x+4)

x = 3/2, x = - 4

b) f (x) = 2x² - 3x - 2

0 = 2x² - 3x - 2

0 = 2x² - 4x + x - 2

0 = 2x (x-2) + 1 (x-2)

0 = (2x+1) (x-2)

x = 2, x = - 1/2