Consider circle H with a 3 centimeter radius. If the length of minor arc RS is

5/2π, what is the measure of ∠RST? Assume that chords RS and TS are congruent.

Given:

Radius = 3 cm

length of minor arc = 5/2π

length of the minor arc = 2 π r (x/360°)

5/2π = 2 π r (x/360°)

5/2 * 3.14 = 2 * 3.14 * 3 (x/360°)

5/6.28 = 18.84 (x/360°)

6.28 (5/6.28) = 6.28 (18.84) (x/360°)

5 * 360° = 118.32x

1800 / 118.32 = x

15.21 = x