The area of a rectangle is 54cm. The length is 2cm more than a x and the width is 5cm less than twice x. Solve for x. Round your answer to the nearest whole number.

A rectangle is a quadrilateral and its area is expressed as the product of its length and width. From the given, we have:

Length = x + 2

Width = 2x - 5

Area = 54 cm^2

Area = Length x Width

Substituting the values,

Area = (x + 2) (2x-5) = 54

54 = 2x^2 - x - 10

2x^2 - x - 64 = 0

We can see that the equation above is a polynomial with a degree of 2 therefore we can usethe Quadratic Formula to solve for x. The quadratic formula will solve two values of x.

x1 = (-b + (√b^2 - (4ac)) / 2a = 5.91

x2 = (-b - (√b^2 - (4ac)) / 2a = - 5.41

Since, for this case, the value x should not result to a negative value for both dimensions thus x is equal to 5.91.