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6 May, 21:55

The hypotenuse of a right triangle is 25m long. The length of one of the legs is 10m less than twice the other. Find the length of each leg.

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  1. 7 May, 01:12
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    (2x-10) ^2+x^2=25^2

    4x^2-40x+100+x^2=625

    5x^2-40x+100-625=0

    5x^2-40x-525=0

    5 (x^2-8x-105) = 0

    5 (x-15) (x+7) = 0

    x-15=0

    x=15 for the short side.

    2*15-10

    30-10=20 for the long side.

    Proof:

    15^2+20^2=25^2

    225+400=625

    625=625
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