A table has an area of 12 ft squared and a perimeter of 16 ft. What are the dimensions of the table?

A) 2 ft by 6 ft

B) 2 ft by 8 ft

C) 4 ft by 3 ft

D) 4 ft by 4 ft

P=2x+2y, y = (p-2x) / 2

a=xy, using y found above in this equation gives you:

a = (px-2x^2) / 2 we are told a=12 and p=16 so

12 = (16x-2x^2) / 2

24=16x-2x^2

2x^2-16x+24=0

2x^2-12x-4x+24=0

2x (x-6) - 4 (x-6) = 0

(2x-4) (x-6) = 0

2 (x-2) (x-6) = 0

So the table is 2 ft by 6 ft.