Find three consecutive odd intergers such that the sum of the largest and twice the smallest is 25

Let the consecutive odd integers be:

x, x + 2, x + 4. Each integer increases by 2

Sum of largest and twice the smallest = 25

(x + 4) + 2 * (x) = 25

x + 4 + 2x = 25

x + 2x = 25 - 4

3x = 21

x = 21/3

x = 7

Recall the consecutive odd integers are x, x + 2, x + 4

7, 7 + 2 = 9, 9 + 2 = 11

7, 9, 11.