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31 May, 08:54

I will mark Brainliest

A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, assuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit? (Use 3.14 for the value of π.)

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  1. 31 May, 11:00
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    The minimum amount of wrapping material needed to cover a biscuit would be equal to the biscuit area. The biscuit is spherical/circle, so the area would be using circle formula. If the area is 200,96, the radius would be:

    circle area = π * r * r

    200.96 = 3.14 * r^2

    r^2 = 200.96/3.14

    r = √64 = 8

    The diameter would be:

    diameter = radius * 2

    diameter = 8*2 = 16
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