The length of a triangel is three times its with. if the perimiter is at its most 112 centemeters, witch is the greates possible value of the with.

a. 2w+2 * (3w) 112

b. 2w+2 * (3w) <112

c. 2w+2 * (3w) >112

d. 2w+2 * (3w) 112

I am assuming you do not mean The length of a triangle and you mean The length of a rectangle because the answer you given are the formula for the perimeter of a rectangle. With that said, the answer is D. 2w+2 * (3w) 112

The perimeter of a rectangle can be found by the following equation:

2L + 2W = P

OR

P = 2L + 2W

The equation P = 2L + 2W is read perimeter = 2 times Length + 2 times width

The Question:

The length of a rectangle is three times its width. if the perimeter is at its most 112 centimeters, which is the greatest possible value of the the width.

The length of a rectangle

This means the perimeter

is

The word is means to use an equal sign

three times its width

This means 3 times w or 3w

The w = width

perimeter is at its most 112

This means <=

< = means less than or equal to

Ok so lets look at our equation

2L + 2W = P

2w + 2 (3w) < = 112