Ask Question
9 September, 18:01

How can one fourthx - 3 = one halfx + 8 be set up as a system of equations?

+3
Answers (1)
  1. 9 September, 19:57
    0
    First, set each half of the equation equal to zero:

    1/4x - 3 = 0

    1/2x + 8 = 0

    Notice how I stacked the equations, lining up "like terms."

    Multiply both equations by "4" to eliminate the fractions:

    (4) 1/4x - 3 = 0 - - > x - 12 = 0

    (4) 1/2x+8 = 0 - - > 2x + 32 = 0

    Add the equations equal: 3x + 20 = 0

    Subtract 20 from both side - 20 - 20

    Simplify 3x = - 20

    Divide both sides by 3 3 3

    Final answer: x = - 20/3
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How can one fourthx - 3 = one halfx + 8 be set up as a system of equations? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers