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8 May, 16:33

What is the vertex of f (x) = 5^2+20-16

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  1. 8 May, 17:04
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    The given equation is f (x) = 29. The graph is a horizontal line, which has no vertex. Perhaps you intend

    ... f (x) = 5x^2 + 20x - 16

    ... = 5 (x^2 + 4x + 4) - 16 - 20

    ... = 5 (x + 2) ^2 - 36

    The vertex is (-2, - 36)
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