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30 November, 23:42

What are the real zeros of the function g (x) = x³ + 2xÆ - x - 2?

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  1. 1 December, 01:01
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    G (x) = x³ + 2 x² - x - 2

    x³ + 2 x² - x - 2 = 0

    x² (x + 2) - (x + 2) = 0

    (x + 2) (x² - 1) = 0

    (x + 2) (x + 1) (x - 1) = 0

    Answer:

    The real zeroes are: x 1 = - 2, x 2 = - 1, x 3 = 1
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