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10 January, 17:50

A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39)

Which are the equations of the directrices?

A. x = ±12/13

B. y=±12/13

C. x=±432/13

D. y=± 432/13

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Answers (1)
  1. 10 January, 20:02
    0
    To solve this problem you must apply the proccedure shown below:

    1. The vertex i at (0, 36) and a focus at (0, 39), then you have:

    a=36

    a^2=1296

    2. The directrix is:

    y=a^2=c

    c=39

    y=1296/39

    y=432/13

    Therefore, the answer is the option D, which is: D. y=± 432/13
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