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20 January, 17:01

If an experiment consists of five outcomes with p (o1) = 0.10, p (o2) = 0.20, p (o3) = 0.30, p (o4) = 0.15, then p (o5) is

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  1. 20 January, 17:20
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    Given an experiment with 5 trials, the sum of probabilities is 1.

    i. e.

    p (o1) + p (o2) + p (o3) + p (o4) + p (o5) = 1

    0.10 + 0.20 + 0.30 + 0.15 + p (o5) = 1

    0.75 + p (o5) = 1

    p (o5) = 1 - 0.75 = 0.25

    p (o5) = 0.25
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