When a driver presses the brake pedal, his car stops with an acceleration of - 2.1 m/s2. How far will the car travel while coming to a complete stop if its initial speed was 13 m/s?

The kinematic equation that will be used for this problem is:

Vf^2 = V1^2 + 2 * a * d, where,

Vf = final velocity = 0 m/s

V1 = initial velocity = 13 m/s

a = acceleration = - 2.1m/s^2

d = distance traveled = ?

Inserting the given values, the equation becomes

0^2 = 13^2 + 2 * - 2.1 * d

0 = 169 + - 4.2*d

169 = 4.2 * d

169/4.2 = d = 40.24

Therefore, d = 40.24 M.

The answer to the question is 25