A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.870 m/s at an angle of 35.0° above the table, and it lands on the magazine 0.0770s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

Thickness of magazine = 9.42 mm.

Explanation:

Considering vertical motion of spider:-

Initial velocity, u = 0.870 sin 35 = 0.5 m/s

Acceleration, a = - 9.81 m/s²

Time, t = 0.077 s

We have equation of motion s = ut + 0.5 at²

Substituting

s = 0.5 x 0.077 - 0.5 x 9.81 x 0.077²

s = 9.42 x 10⁻³ m = 9.42 mm

Thickness of magazine = 9.42 mm.