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1 September, 04:09

What is the temperature change in 355 ml of water upon absorption of 34 kj of heat? (the specific heat capacity of water is 4.184 j/g∘c.) express your answer in degrees celsius?

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  1. 1 September, 07:04
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    Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

    Heat = mC (T2-T1)

    We have to determine the value of (T2-T1) which is the temperature change. To do this, we simply substitute the values given above. We do as follows:

    Heat = mC (T2-T1)

    34 kJ (1000 J / kJ) = 355 mL (1 g / mL) (4.184 J / g-C) (T2-T1)

    (T2-T1) = 22.89 degrees Celsius or Kelvin

    THerefore, the temperature change of the abosrption of 34 kJ of heat by water would be 22.89 degrees Celsius.
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