A pair of fuzzy dice is hanging by a string from your rearview mirror. while you are accelerating from a stoplight to 28 m/s in 6.0 s, what angle does the string make with the vertical? (assume your acceleration is constant.)

Question

Physics

Susan Rowe

13 September, 05:08

A pair of fuzzy dice is hanging by a string from your rearview mirror. while you are accelerating from a stoplight to 28 m/s in 6.0 s, what angle does the string make with the vertical? (assume your acceleration is constant.)

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Harrison Gallegos · Answer 1

We can use the formula of motion in physics (2nd law od newton) in this problem:

x direction: Fsin ∅ = ma

y direction: Fcos ∅ - mg = 0

∅ is equal to sin ∅ / cos ∅ or x/y

tan ∅ = ma / mg = a / g

Applying acceleration formula:

v = vo + at; 28 = 0 + 6a; a = 4.67 m/s^2

∅ = tan-1 (a/g) = tan-1 (4.67/9.81) = 25.4 degrees.