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Today, 05:34

A wire of length 25.0 cm carrying a current of 4.21 mA is to be formed into a circular coil and placed in a uniform magnetic field B with arrow of magnitude 5.55 mT. Suppose the torque on the coil from the field is maximized.

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  1. Today, 07:10
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    1.162 x 10^-7 Nm

    Explanation:

    length of wire, l = 25 cm

    l = 2 π r

    where, r is the radius of circular loop

    25 = 2 x 3.14 x r

    r = 3.98 cm

    Magnetic field, B = 5.55 mT = 5.55 x 10^-3 T

    Current, i = 4.121 mA = 4.21 x 10^-3 A

    Torque, τ = i x A x B

    τ = 4.21 x 10^-3 x 3.14 x 0.0398 x 0.0398 x 5.55 x 10^-3

    τ = 1.162 x 10^-7 Nm

    Thus, the maximum torque in the coil is 1.162 x 10^-7 Nm.
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