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11 June, 04:27

Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 * 10-5 coulombs is placed on q and a force of 5.2 N is applied.

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  1. 11 June, 06:32
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    E = F/q

    = 5.2 N / (7 * 10⁻⁵) C

    = 7.429 * 10⁴ N/C
  2. 11 June, 08:04
    0
    Formula for feild strength = F/q

    q=7.0^10-5 coulombs

    F=5.2 N

    E=5.2 / 7.0^10-5

    E=
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