Find the orbital period (in years) of an asteroid whose average distance from the sun is 27

a. u. only enter the number, not the units

Using Kepler's third law which is defined as the square of the average distance is directly proportional to the cube of the period. It is expressed as P^2 = a^3, Given that the a = average distance is given, the period would be much easier to compute. P = sqrt (27^3) = 140