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5 June, 18:26

A stretched spring has an elastic potential energy of 35 J when it is stretched 0.54 m. What is the spring constant of the spring? Round your answer to two significant figures.

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  1. 5 June, 19:25
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    240 is the correct answer
  2. 5 June, 20:14
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    The spring constant of the spring is 240.05 N/m according to the information on the question above. This problem can be solved using the spring potential energy formula which stated as PE = 1/2 * k * x^2 where PE is the spring's potential energy, k is the constant of the spring, and x is the stretched displacement. (Calculation: 240.05=35*2 / (0.54^2)
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